ANSWER TO QUESTION # 5:

We know that there were five droves with an equal number in each drove, and.therefore,the number must be divisible by 5. As every one of the eight dealers bought the same number of animals, the number must also be divisible by 8. This leads us to the conclusion that the number must be a multiple of 40. Now the highest possible multiple of 40 that will work is 120, and this number could be made up in one of two ways - 1 cow, 23 sheep and 96 pigs or 3 cows, 8 sheep and 109 pigs. But the first does not fit in because the animals consisted of 'Cows, Sheep and Pigs' and a single 'Cow! is not 'Cows'. Therefore,the second possibility is the correct answer.